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6x^2+17x+3=0
a = 6; b = 17; c = +3;
Δ = b2-4ac
Δ = 172-4·6·3
Δ = 217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{217}}{2*6}=\frac{-17-\sqrt{217}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{217}}{2*6}=\frac{-17+\sqrt{217}}{12} $
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